3. 6 Tiebreakers
3.6 同分决胜分
During the course of a Swiss tournament,
在瑞士轮的比赛过程中，
Some players will accumulate the same number of match wins as other players.
当一些选手所积累的胜局数和其他选手相同时。
A three tiebreaker system will be used and applied to accurately rank players in the tournament.
将用三种同分决胜分公式用来在比赛中准确排名选手。
A tiebreaker may be a positive or a negative number.
这个同分决胜分可能是一个正数或者负数。
The Cryptozoic Tournament Tracker software uses this tiebreaker system.
卡牌客比赛纪录软件使用这些同分决胜分公式。
Tiebreaker #1 (T1): Win/Loss Sum
＃1（T1）：胜/负数
Tiebreaker #1 represents the performance of opponents that a player has played over the course of the tournament.
当选手所有的比赛完成时其对应选手的成绩，
Players that played against stronger opponents will be ranked higher within the tournament.
选手在对应更强的对手时将会在比赛中获得更高的等级。
The formula to calculate the number is:
计算公式：
Total the number of points each opponent contributes.
总分为每个对手贡献分数。
Opponents contribute +1 point for each win they accumulate throughout the tournament and -1 for each loss they accumulate throughout the tournament.
对手在整个比赛中每胜一场+1分，每负一场-1分。
Each single opponent may never contribute less than -3 points to a player’s first tiebreaker.
在选手的第一个tiebreaker中每一个对手不会少于-3.
A bye does not contribute any points towards a player’s tiebreaker.
轮空对于每个选手的tiebreaker都没有分数。
Example: Scott has played against three opponents and has one bye.
例如： Scott 四战三胜一场轮空。
Scott's fourth-round opponent has four wins and zero losses (+4).
Scott 的第四轮对手四胜零负得分为+4.
Scott's third -round opponent has two wins and two losses (+0).
Scott 的第三轮对手两胜两负得分为0.
Scott's second-round opponent has zero wins and four losses (-3).
Scott 的第二轮对手零胜四负得分为-3.
Scott had a bye during the first round (+0).
Scott 轮空得分为0.
To determine Scott's T1, add up all of the point contributions: +4, +0, -3 (because each single opponent may never contribute less than -3 points to a player’s tiebreaker).and +0 (A bye contributes no points).for a total of +1.
可以确定Scott 的T1分数，所有所得分数相加：+4，+0，-3（因为在选手的第一个tiebreaker中每一个对手不会少于-3.
）和+0（轮空不得分）。所以总计得分+1。
Tiebreaker #2 (T2): First Tiebreaker Sum
＃2（T2）：第一Tiebreaker 分数
Tiebreaker #2 represents the performance of the opponents that all of a player’s opponents played.
T2代表的是全部选手的对手比赛的对手成绩。
Players that played against opponents who consistently played against stronger opponents throughout the tournament will be ranked higher.
选手在对应的对手在整个比赛中所对应的对手更强的将获得更高的排名。
The formula to calculate the number is:
计算公式：
Total the sum of Tiebreaker #1 (T1) for all opponents that player played.
总分为选手的所有对手的T1总和。
Example: Jeff has played against five opponents.
例如： Jeff 所对应的对手有五个。
Jeff's first-round opponent’s T1 is +3.
Jeff 第一轮对手的T1得分为+3。
Jeff's second-round opponent's T1 is -2.
Jeff 第二轮对手的T1得分为-2。
Jeff's third-round opponent's T1 is +5.
Jeff 第三轮对手的T1得分为+5。
Jeff's fourth -round opponent's T1 is 0.
Jeff 第四轮对手的T1得分为0。
Jeff's fifth-round opponent's T1 is +4.
Jeff 第五轮对手的T1得分为+4。
To determine Jeff's Tiebreaker #2, add up all T1 values from all of his opponents: +3, -2, +5, +0, and +4, for a total of +10.
可以确定Jeff的T2分数为，为选手的所有对手的T1总和+3，-2，+5 ，+0，+4，总计+10。
Tiebreaker #3 (T3): Timing
＃3（T3）：
Tiebreaker #3 represents the importance of the rounds in which you lost.
T3所代表的是你所负于对手的重要轮次。
Players losing in later rounds will be ranked higher within the tournament.
选手所负的轮次越靠后，所得的分数就越靠前。
The formula to calculate this number is:
计算公式：
The sum of the squares of the rounds in which you lost .
分数为负与对手的轮次的平方的总和。
Example: Jake has five wins and two losses.
例如： Jake 比赛结果五胜两负。
Jake lost in Round 5 and again in Round 6.
Jake 所负轮次为第五轮和第六轮。
To determine Jake’s Tiebreaker #3, add up the squares of the rounds in which he lost: 25 + 36 = 61
可以确定Jake的T3分数为，他所负轮次的平方相加：25+ 36 = 61
Official sanctioned events use a tie-breaker system to determine which Duelist ranks higher when both have the same
number of Match Wins. Duelists earn Points based on how well they perform during a Match.
Outcome Points
Win 3
Draw 1
Loss 0
Example: A Duelist has completed 3 rounds of a tournament, and currently has 2 Wins and 1 Draw. The Duelist has 7
Points (3 Points for each Win, and 1 Point for each Draw). The Duelist’s XX equals 7.
Duelists are first ranked based on how many points they have accumulated during the course of a tournament. In
addition to points, KTS uses a method to track how strong or weak your tournament schedule has been. It tracks the
record of each of your opponents, and the record of your opponent’s opponents to determine the final tiebreakers. This
number can be portrayed as follows:
XXYYYZZZ
XX Total amount of Points the Duelist has earned during the course of the tournament.
YYY Your opponents’ match-win percentage.
ZZZ Your opponent’s opponents’ match-win percentage.
Example: A Duelist at a Yu-Gi-Oh! Championship series event has a tie-breaker number of 33726677. The number
breaks down as follows:
33 (XX): Total amount of points the Duelist earned during the tournament.
726 (YYY): Their opponents’ match-win percentage.
677 (ZZZ): Their opponent’s opponents’ match-win percentage.
公认大会出线者的判定：
A.计分：
MATCH胜利计3分，MATCH平局计1分，MATCH败北计0分。
例如一位玩家在3轮中2胜1平，计7分。
B.玩家的TIE-BREAKER(出线者)号码：
格式为XXYYYZZZ的8个阿拉伯数字。
XX代表玩家的总分。YYY代表玩家的对手的MATCH平均胜率。ZZZ代表玩家的对手的对手的MATCH平均胜率。
例如一位玩家的出线者号码是33726677，表示他在本场大会中计33分，他的对手的MATCH平均胜率是72.6%，他的对手的对手的MATCH平均胜率是67.7%.
玩家的出线者号码直观地代表了玩家的强度，用来对参赛玩家进行排名。
关注公众号
发表于 2012-6-22 16:33:44
提升卡
变色卡
显身卡
